68000 Code to Sum Values in a Range That are Multiples of a Value
Write an MC6800 program that adds up all numbers divisible by 11 between two limits,
e.g., from 15 to 400
• Your program must use at least one loop
• Your program should store the sum in memory location $300; check the resultafter running the program
• Start your program at address $400
• Include all necessary global and local comments
• For this program, you may not use numbers for any addresses except in an ORGdirective (use labels instead for other addresses)
• Be sure to run your program and check the results
• The name of your program should be your last name (or its first eight letters)
• Submit your program file (with extension .X68) along with representative resultsas paper copies in the class on or before the due date.
Solution
program.X68
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* Title :
* Written by :
* Date :
* Description:
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ORG $400
START: ; first instruction of program
LEA FIRST,A0
MOVE.L (A0),D1 ; read first limit in D1
LEA LAST,A0
MOVE.L (A0),D2 ; read last limit in D2
MOVE.L #0,D3 ; D3 will contain the sum, initialize to 0
MOVE.L #16,D4 ; D4 is always 16
LOOP:
MOVE.L D1,D0 ; put current number in D0 for division
DIVU #11,D0 ; divide by 11
LSR.L D4,D0 ; put the remainder at lower 16 bits by shifting to the right
CMP.W #0,D0 ; see if the remainder is zero
BNE NEXT ; if not, is not divisible by 11, go to next
ADD.L D1,D3 ; if it’s divisible, add to the sum
NEXT:
ADD.L #1,D1 ; go to next number
CMP.L D2,D1 ; compare current number with upper limit
BLE LOOP ; continue while we don’t go above the upper limit
LEA ADDR,A0
MOVE.L (A0),A0 ; read address to save sum in A0
MOVE.L D3,(A0) ; save sum in the result address
SIMHALT ; halt simulator
FIRST: DC.L 15 ; lower limit
LAST: DC.L 400 ; upper limit
ADDR: DC.L $300 ; address to save result
END START ; last line of source
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